Some of the most satisfying questions on the whole Civil Service Exam are number-series questions: you stare at a row of numbers like "2, 5, 8, 11, ___" and suddenly the hidden rule clicks and the answer appears. This chapter teaches you to make that click happen on demand — through a systematic checklist rather than lucky guessing — and it also covers the number-theory facts (factors, multiples, primes, divisibility) that quietly power many exam items. By the end you'll have a reliable method for both.
This topic joins two related skills. Number series questions show a sequence with a missing term and ask you to find the pattern and fill the gap. Number theory questions test facts about how whole numbers behave: factors, multiples, prime numbers, greatest common factor (GCF), least common multiple (LCM), and divisibility rules.
On the Civil Service Exam, number-series items are a staple of Numerical Reasoning — you can count on several — and number-theory facts appear both directly and inside other problems (simplifying fractions needs GCF; finding "when events coincide" needs LCM). Together they touch 5 to 9 items on a typical exam.
The difficulty ranges from easy to challenging. The easy series follow one simple rule; the hard ones interleave two patterns or hide a "pattern of the differences." The secret is not raw cleverness but a fixed order of things to check — the same checklist every time — so you never freeze in front of a sequence again.
After completing this lesson you will be able to:
You should be comfortable with:
A quick refresher on squares and cubes, because they hide inside many series. Squares: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 (that's 1² through 10²). Cubes: 1, 8, 27, 64, 125 (1³ through 5³). Memorizing these two short lists lets you instantly recognize a "squares series" or "cubes series" that would otherwise stump you.
Pattern recognition and number sense are everywhere:
Beyond the exam, this topic builds "number sense" — a feel for how numbers relate — which quietly makes all other math faster and more accurate.
We'll handle series first, then number theory.
When you see a sequence, run through these in order. The first one that fits is almost always the answer.
1. Constant difference (arithmetic). Each term adds (or subtracts) the same number.
2, 5, 8, 11, ___ → add 3 each time → 14.
2. Constant ratio (geometric). Each term multiplies (or divides) by the same number.
3, 6, 12, 24, ___ → multiply by 2 → 48.
3. Changing difference. The differences themselves follow a pattern.
1, 2, 4, 7, 11, ___ → differences are 1, 2, 3, 4, so add 5 → 16.
4. Alternating / interleaved. Two separate series woven together — often the odd positions follow one rule and the even positions another.
1, 10, 2, 20, 3, ___ → odd positions 1, 2, 3…; even positions 10, 20, …; next is an even position → 30.
5. Squares, cubes, primes, or Fibonacci.
1, 4, 9, 16, ___ → perfect squares → 25. 1, 8, 27, 64, ___ → perfect cubes → 125. 2, 3, 5, 7, 11, ___ → prime numbers → 13. 1, 1, 2, 3, 5, 8, ___ → each term is the sum of the two before it (Fibonacci) → 13.
6. Multiply-and-add rules. Each term is transformed by "×k then ± c."
1, 3, 7, 15, 31, ___ → each term is ×2 then +1 → 63.
Underneath the sequence, write the differences between consecutive terms. If those differences are constant, you have type 1. If the differences grow in a pattern, type 3. If differences don't help, try ratios (divide each term by the previous) for type 2. If neither works, suspect an alternating series and look at every other term. Finally, compare against squares, cubes, and primes.
Golden rule: once you think you've found the rule, test it on at least two gaps, not one. A rule that fits a single gap might be a coincidence; a rule that fits the whole sequence is the answer.
Analogy: Primes are the "atoms" of numbers — you can't break them into smaller whole-number factors, and every other number is built by multiplying primes together, just as molecules are built from atoms.
Fast method using prime factorization: 12 = 2² × 3 and 18 = 2 × 3².
Memory tip: GCF is the Greatest thing that fits into both (so it's small-ish); LCM is the Least thing both fit into (so it's big-ish). GCF ≤ each number ≤ LCM.
Some series are best understood by their position n (1st term, 2nd term, …). A term might equal n², or n² + n, or n³. Recognizing "this is just the position squared" cracks a series that resists differences.
2, 6, 12, 20, 30, ___ → these are n² + n (1+1, 4+2, 9+3, 16+4, 25+5) → next is 36 + 6 = 42.
A special fast-growing type is the factorial-style series, where each term multiplies by the next counting number:
1, 2, 6, 24, 120, ___ → ×2, ×3, ×4, ×5 → next is ×6 → 720.
When a series explodes upward far faster than doubling, suspect a growing multiplier like this.
A useful number-theory idea for the exam: if a number leaves a remainder when divided, subtract the remainder to get a number that divides evenly. This turns a remainder problem into a plain GCF problem.
What is the largest number that divides both 62 and 92, leaving a remainder of 2 in each case? Subtract the remainder: it must divide 62 − 2 = 60 and 92 − 2 = 90 exactly. So the answer is GCF(60, 90) = 30.
These give a fast yes/no without dividing:
Example: Is 3,471 divisible by 3? Digit sum 3 + 4 + 7 + 1 = 15, which is divisible by 3, so yes. Divisible by 9? 15 is not a multiple of 9, so no.
With the toolkit assembled, let's picture it, list it, and drill it.
| Concept | Rule | Example |
|---|---|---|
| Arithmetic series | add a constant d | 3, 7, 11, 15 (d = 4) |
| Geometric series | multiply by a constant r | 2, 6, 18, 54 (r = 3) |
| nth term (arithmetic) | first + (n − 1)·d | 5th of 3,7,11… = 3 + 4·4 = 19 |
| Prime factorization | write as product of primes | 60 = 2²·3·5 |
| GCF (via primes) | product of lowest shared powers | GCF(12,18)=2·3=6 |
| LCM (via primes) | product of highest powers present | LCM(12,18)=2²·3²=36 |
| GCF × LCM | equals product of the two numbers | 6 × 36 = 12 × 18 = 216 |
The handy identity: for any two numbers, GCF × LCM = the product of the numbers. If you know three of these four, you can find the fourth. For 12 and 18: 6 × 36 = 216 = 12 × 18. ✓
| Clue in the series | Likely rule |
|---|---|
| terms grow by the same gap | constant difference |
| terms roughly double/triple | constant ratio |
| gaps grow 1, 2, 3, … | changing difference |
| numbers zig-zag up and down | two interleaved series |
| 1, 4, 9, 16 / 1, 8, 27 | squares / cubes |
| 2, 3, 5, 7, 11 | primes |
| each term = sum of previous two | Fibonacci |
| jumps too big for adding | try ×k ± c |
For number theory: "largest… equal groups / biggest tile / simplify" → GCF; "smallest… again together / common denominator / next time both" → LCM.
Step 1 — For a series, write the differences between consecutive terms. ↓ Step 2 — Check the checklist in order: constant difference → constant ratio → changing difference → alternating → squares/cubes/primes/Fibonacci → ×k ± c. ↓ Step 3 — State the rule in words ("multiply by 2 then add 1"). ↓ Step 4 — Test it on two or more existing gaps to be sure. ↓ Step 5 — Apply it to the missing term and select the answer.
For number-theory items: decide whether the situation wants GCF (splitting/grouping) or LCM (coinciding/repeating), then use prime factorization to compute it.
Example 1. Find the next term: 7, 14, 21, 28, ___. Solution: Constant difference of 7 → 35. Difficulty: ★☆☆☆☆
Example 2. Find the next term: 1, 3, 9, 27, ___. Solution: Constant ratio ×3 → 81. Difficulty: ★☆☆☆☆
Example 3 (changing difference). Find the next term: 2, 3, 6, 11, 18, ___. Thinking: Differences are 1, 3, 5, 7 (odd numbers) → next difference is 9. Solution: 18 + 9 = 27. Check: the differences 1, 3, 5, 7, 9 are consistent. ✓ Difficulty: ★★☆☆☆
Example 4 (alternating). Find the next term: 5, 20, 6, 19, 7, ___. Thinking: Odd positions: 5, 6, 7 (add 1). Even positions: 20, 19, … (subtract 1). The blank is an even position → 19 − 1. Solution: 18. Difficulty: ★★★☆☆
Example 5 (squares nearby). Find the next term: 2, 5, 10, 17, 26, ___. Thinking: These are 1²+1, 2²+1, 3²+1, 4²+1, 5²+1 → next is 6² + 1. Solution: 36 + 1 = 37. Alternative: differences are 3, 5, 7, 9 → next 11 → 26 + 11 = 37. Same answer, two routes. ✓ Difficulty: ★★★☆☆
Example 6 (multiply-and-add). Find the next term: 3, 7, 15, 31, 63, ___. Thinking: Each term is ×2 then +1: 3→7→15→31→63. Solution: 63 × 2 + 1 = 127. Difficulty: ★★★☆☆
Example 7 (GCF word problem). A florist has 24 roses and 36 tulips and wants to make identical bouquets using all the flowers with none left over. What is the greatest number of bouquets? Thinking: "Identical groups, greatest number, nothing left" → GCF. Solution: 24 = 2³ × 3; 36 = 2² × 3². GCF = 2² × 3 = 12 bouquets (each with 2 roses and 3 tulips). Difficulty: ★★★☆☆
Example 8 (LCM word problem). At a terminal, one jeepney leaves every 8 minutes and another every 12 minutes. If both leave together at 6:00 a.m., when will they next leave together? Thinking: "Next time both together" → LCM. Solution: 8 = 2³, 12 = 2² × 3. LCM = 2³ × 3 = 24 minutes. Next together at 6:24 a.m. Difficulty: ★★★★☆
Example 9 (divisibility reasoning). Which of these is divisible by both 3 and 4: 132, 146, 150, 168? Thinking: Divisible by 4 → last two digits divisible by 4; by 3 → digit sum divisible by 3. Solution: 168: last two digits 68 ÷ 4 = 17 ✓, digit sum 1 + 6 + 8 = 15 divisible by 3 ✓ → 168. (132 is divisible by 4 and by 3 too — 32÷4=8, 1+3+2=6 — so check the intended single answer carefully; both 132 and 168 qualify, which is exactly the kind of "more than one fits" trap to watch. If only one choice may be picked, the item is flawed; on a real exam, pick the one the key intends, but knowing why both work is the mastery.) Difficulty: ★★★★☆
Example 10 (odd-one-out). Which number does not belong: 121, 144, 169, 180, 196? Thinking: The others are perfect squares (11², 12², 13², 14²). 180 is not. Solution: 180 is the odd one out. Check: 121 = 11², 144 = 12², 169 = 13², 196 = 14². ✓ Difficulty: ★★★☆☆
Example 11 (decreasing changing difference). Find the next term: 100, 96, 88, 76, 60, ___. Thinking: Differences are −4, −8, −12, −16 (going down by 4 more each time) → next is −20. Solution: 60 − 20 = 40. Difficulty: ★★★☆☆
Example 12 (factorial-style). Find the next term: 1, 2, 6, 24, 120, ___. Thinking: Each term multiplies by the next counting number (×2, ×3, ×4, ×5). Solution: 120 × 6 = 720. Difficulty: ★★★★☆
Example 13 (Fibonacci-style). Find the next term: 2, 3, 5, 8, 13, ___. Thinking: Each term is the sum of the two before it. Solution: 8 + 13 = 21. Difficulty: ★★★☆☆
Example 14 (LCM word problem). What is the smallest number of candies that can be shared equally among 6, 8, or 12 children with none left over? Thinking: "Smallest number that 6, 8, and 12 all divide into" → LCM. Solution: 6 = 2·3, 8 = 2³, 12 = 2²·3 → LCM = 2³ · 3 = 24 candies. Difficulty: ★★★★☆
For number series, don't guess — run the checklist: write the differences first; if not constant, look for a pattern in the differences, then ratios, then an interleaved pair, then squares/cubes/primes/Fibonacci, and finally a ×k ± c rule. Always verify your rule on two gaps before answering. For number theory, know the vocabulary (factor, multiple, prime, composite), remember that 1 is not prime and 2 is the only even prime, and use prime factorization to get both GCF (lowest shared powers — for grouping) and LCM (highest powers — for coinciding events). Lean on divisibility rules to test numbers instantly. Systematic checking, not cleverness, is what turns this topic into easy points.
| Topic | Key point |
|---|---|
| Series checklist | differences → ratios → interleave → squares/cubes/primes → ×k±c |
| Verify | test the rule on 2+ gaps |
| Squares | 1,4,9,16,25,36,49,64,81,100 |
| Cubes | 1,8,27,64,125 |
| Prime facts | 1 not prime; 2 only even prime |
| GCF | lowest shared prime powers (grouping/simplify) |
| LCM | highest prime powers present (coinciding) |
| Identity | GCF × LCM = product of the numbers |
| Div by 3/9 | digit sum divisible by 3/9 |
| Div by 4 | last two digits divisible by 4 |
I found a rule but I'm not sure it's the intended one. What do I do? Test it on every gap in the sequence. The correct rule fits all of them; a coincidental rule breaks somewhere. If two different rules both fit every term and give different next values, the item is ambiguous — pick the simpler rule.
Is 1 a prime number? No. A prime must have exactly two distinct factors; 1 has only one factor (itself). And 1 is not composite either — it's in a category of its own.
How do I find LCM quickly for the exam? Prime-factorize both numbers and take the highest power of every prime that appears. Or, if you already have the GCF, use LCM = (product of the numbers) ÷ GCF.
When is it GCF and when is it LCM? GCF for "split into the largest equal groups / biggest tile / simplify a fraction." LCM for "when do repeating events happen together again / smallest common denominator."
Do I need to memorize primes? Knowing the primes up to about 30 (2, 3, 5, 7, 11, 13, 17, 19, 23, 29) is very helpful and quick to memorize. Beyond that, use divisibility rules to test.
Tick them all and both number series and number theory become dependable, quick points — plus you've sharpened the number sense that speeds up every other numerical topic.
Put it to the test with 1,625 practice questions on this topic.